Question

50ml of 0.5m oxalic acid is needed to neutralize 25ml of sodium hydroxide solution. The amount of naoh in 50ml

Answer 1

Answer:

HH2C2O4 +2NaOH → Na2C2O4+2H2O

Meq of H2C2O4 = Meq of NaOH

50×0.5×2 = 25× N{NaOH}×1

M_{NaOH} = N_{NaOH} = 2×M∴M

NaOH

=N

NaOH

=2 M ; since n-factor is 1

Now, 1000ml solution = 2×40gram NaOH

∴50 ml solution = 4 gram NaOH.

Hence, The amount of NaOHNaOH in 50\ mL50 mL of the given sodium hydroxide solution is 4 gram.