Question

50ml of 1 M oxalic acid is shaken with 0.5g of wood charcoal . the final concentration of the solution after adsorption is 0.5 M. what is the amount of oxalic acid adsorbed per g of carbon

Answer 1

Here is answer..... Hope u will understand properly

Answer 2

The amount of oxalic acid adsorbed per g of carbon is 6.30 g.

Explanation:

We will calculate the number of moles present in 50 ml of 1 M oxalic acid as follows.

$\frac{50 L}{1000} \times 1 M$

         = 0.05 moles of oxalic acid

Remaining moles of oxalic acid after the adsorption are as follows.

$\frac{50 L}{1000} \times 0.5 M$

         = 0.025 moles

Therefore, number of moles absorbed on charcoal are as follows.

        (0.05 - 0.025) moles

      = 0.025 moles of oxalic acid

This means that 5 g of charcoal absorbs 0.025 moles. Hence, moles absorbed by 1 g are as follows.

    $1 g \text{absorbs} = \frac{0.025}{0.5}$

              = 0.05 moles of oxalic acid

Therefore, amount of oxalic acid absorbed per gram of charcoal is as follows.

       $0.05 \times 126 g/mol$  

      = 6.30 g

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