Question

50ml of an aqueous solution of glucose C6H12O6 (Molar mass 180 g/mol) contains 6.02 x 1022 molecules. The concentration solution will be(A) 0
1 M(B) 0.2 M(C) 1.0 M(D) 2.0 M​

Answer 1

The concentration of the glucose solution will be (D) 2.0 M​.

- No of molecules of glucose = 6.02 x 10²²

- No of moles of glucose = 6.02 x 10²² / 6.02 x 10²³ = 10⁻¹ = 0.1 mole

- Volume of glucose solution = 50 ml = 0.05 litre

- Molarity = No of moles / Volume of solution

⇒ M = 0.1 / 0.05 = 2 M

- Hence the correct answer is option (D)

Answer 2

The concentration of the glucose solution will be (D) 2.0 M​.

- No of molecules of glucose = 6.02 x 10²²

- No of moles of glucose = 6.02 x 10²² / 6.02 x 10²³ = 10⁻¹ = 0.1 mole

- Volume of glucose solution = 50 ml = 0.05 litre

- Molarity = No of moles / Volume of solution

⇒ M = 0.1 / 0.05 = 2 M

- Hence the correct answer is option (D)