Question

50ml of ethanol (d=0.79g/mol) is dissolved by 400ml of water. what is the concentration of ethanol in this solution​

Answer 1

Answer:

ethanol (d=0.79g/mol) is dissolved by 400ml of water. what is the concentration of ethanol in this solution .

amount of water is required to make 10% ethanol in water solution using 10 ml of pure water. calculate volume % of ethanol .

Answer 2

Answer:

The concentration of ethanol in the solution ( W/V % ) measured is $8.7\%$.

Explanation:

Data given,

The volume of ethanol,$V_{ethanol}$ = $50ml$

The volume of water, $V_{water}$ = $400ml$

The density of ethanol, ρ = $0.79g/ml$

The concentration of ethanol in the solution ( W/V % ) =?

As we know,

• Concentration ( W/V % ) = $\frac{m_{ethanol}}{V_{solution}} \times 100$

Here,

• $m_{ethanol}$ = Mass of ethanol
• $V_{solution}$ = Volume of solution = $V_{ethanol} + V_{water}$ = $50 +400$ = $450ml$

Now, we have to find out the mass of ethanol.

• Density = $\frac{mass}{volume}$
• Mass of ethanol = density × volume  = $0.79 \times 50$ = $39.5g$

Now, after putting the calculated value of ethanol's mass and the volume of solution in equation (1), we get:

• Concentration ( W/V % ) = $\frac{39.5}{450} \times 100$ = $8.7\%$

Hence, the concentration of ethanol in the solution ( W/V % ) measured is $8.7\%$.