Question

50ml of standard hard water containing 0.28g of pure CaCO3 per liter, consumed 16ml of EDTA solution. 50ml of water sample consumed 15ml of the same EDTA solution. After boiling the same sample consumes 12ml of EDTA solution, using Eriochrome black T as an indicator. Analyze the total, temporary and permanent hardness of water sample in ppm

Answer 1

Answer:

288.36

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Answer 2

Answer:

1. Total hardness of water = 279 ppm.
2. Permanent hardness of water = 223.2 ppm.
3. Temporary hardness of water = 55.8 ppm.

Explanation:

The standard water contains .28 g of CaCO3/l.

1000 ml of standard hard water (SHW), therefore, contain 280 mg of CaCO3.

1 ml of standard water = 280/1000 = .28 mg of CaCO3 equivalent.

15 ml of EDTA solution = 50 ml of SHW contains 50×.28⇒14 mg of CaCO3 equivalent.

1 ml of EDTA solution = 14/15 =.93 mg of CaCO3 equivalent.

Hardness of water:

50 ml of water= 15 ml of EDTA solution

=15×.93 ⇒ 13.95 mg of CaCO3 equivalent.

1000 ml of water=13.95/50×1000⇒ 279 mg of CaCO3 equivalent.

Hence, hardness of water = 279 mg/l or ppm.

Permanent hardness of water:

50 ml of water (after boiling)= 12 ml of EDTA solution

=12×.93⇒11.16 mg of CaCO3 equivalent.

1000 ml of water=11.16/50×1000⇒ 223.2 mg of CaCO3 equivalent.

Hence, permanent hardness of water = 223.2 ppm.

Temporary hardness of water:

Temporary hardness of water = (Total hardness -Permanent hardness)

So,

Temporary hardness of water = 279 – 223.2 = 55.8 ppm.

Answers,

Total hardness of water = 279 ppm.

Permanent hardness of water = 223.2 ppm.

Temporary hardness of water = 55.8 ppm.

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