50n²+30n+30=0 find n value
Answers
Answer:
Changes made to your input should not affect the solution:
(1): "n2" was replaced by "n^2".
Step by step solution :
STEP
1
:
Trying to factor by splitting the middle term
1.1 Factoring n2+301n-12132
The first term is, n2 its coefficient is 1 .
The middle term is, +301n its coefficient is 301 .
The last term, "the constant", is -12132
Step-1 : Multiply the coefficient of the first term by the constant 1 • -12132 = -12132
Step-2 : Find two factors of -12132 whose sum equals the coefficient of the middle term, which is 301 .
-12132 + 1 = -12131
-6066 + 2 = -6064
-4044 + 3 = -4041
-3033 + 4 = -3029
-2022 + 6 = -2016
-1348 + 9 = -1339
-1011 + 12 = -999
-674 + 18 = -656
-337 + 36 = -301
-36 + 337 = 301 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -36 and 337
n2 - 36n + 337n - 12132
Step-4 : Add up the first 2 terms, pulling out like factors :
n • (n-36)
Add up the last 2 terms, pulling out common factors :
337 • (n-36)
Step-5 : Add up the four terms of step 4 :
(n+337) • (n-36)
Which is the desired factorization
Equation at the end of step
1
:
(n + 337) • (n - 36) = 0