Question

50pts...solve this one......
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Answer 1

Step-by-step explanation:

let one part be x, then other part is (3600 - x)

Case 1 : SI = (x * 9 * 1) /100

             => SI = 9x/100

Case 2: SI = [(3600-x)*10*1]/100

              => SI = (3600-x)/10

according to problem, 

9x/100  +  (3600-x)/10 = 333

or, (9x + 36000-10x) = 33300

or, -x + 36000 = 33300

or,  x = 36000-33300

or x = 2700

two parts are 2700 and 900

Answer 2

Given :----

• Total Principal = Rs.3600
• Rate = 9% of first part
• Rate = 10% of second part
• Total SI from both = Rs.333

To Find :----

• Both Parts ?

Formula used :-----

• SI = P×R×T/100
• SI = Amount - Principal
• Alligation Method

we can solve it by 2 methods ..

• Basic Method , taking x .
• Alligation Method .

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$\pink{\bold{\underline{\underline{Solution(1)}}}}$

let one part be x

then other part is (3600 - x)...

Case 1 : SI = (x * 9 * 1) /100

=> SI = 9x/100

Case 2: SI = [(3600-x)*10*1]/100

=> SI = (3600-x)/10

Now it is given that we get, total 333Rs. SI,

so,

9x/100 + (3600-x)/10 = 333

→ (9x + 36000-10x) = 33300

→ (-x) + 36000 = 33300

→ x = 36000-33300

→ x = 2700

So, other part = 3600-2700 = 900 .

Hence, Both parts were 2700 and 900 .

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$\red{\bold{\underline{\underline{Solution(2)}}}}$

Let try it with alligation Method Now,

Lets Find out the Total rate on which we get total SI of Rs.333 .

Rate = SI×100/(P×T)

→ Rate = 333×100/3600×1 = 9.25% ..

Now, use alligation ,,, Rest 2 % rate we have 9% and 10% .

so,

9%. 10%

9.25%

(10-9.25). (9.25-9)

= 0.75. 0.25

= 0.75:0.25 = 3 : 1 .

so, break 3600 in ratio 3:1 we get,

Part 1 = 3600×3/4 = 2700

Part 2 = 3600×1/4 = 900 .

Hence , both parts were Rs.2700 and Rs. 900 ...

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(Hope it Helps you)