Physics, asked by ashenafasefa779, 1 day ago

51. A car moving with uniform acceleration travels 36m during the 4th second and 48m during the 6th second.

What is the distance covered by the car in the first 8

Answers

Answered by priyanshubisht019

3

Answer:

the car moving in 4s = 36 m

then the car moving in 2s= 36÷2

= 18m

the car moving in 6s = 48m

so the car move in 8s,= 6s + 8s

= 36m + 18m

= 54m

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