Question

51. Correct variation of velocity of an electron in nth Bohr
orbit of H-atom is​

Answer 1

Answer:

You can say that velocities are in arithmetic progression

v1 :v2 : v3: v4 ....... : vn = 1:2:3:4 ....... :n

Answer 2

Answer:

$v = \sqrt{\dfrac{kZe^{2} }{mr} }$

Explanation:

Since when electron is revolving in respective orbit then it experience a centripetal force along with the force of attraction between nucleus and revolving electron and both forces are equal.

$F_{centripetal\ force} =F_{attraction\ force}$

$m\dfrac{v^{2} }{r} = \dfrac{kZe^{2} }{r^{2} }$.....................(1)

where m =mass of electron , r = radius of nth orbit, e = charge on electron.

After solving (1) we get,

Velocity of an electron in nth Bohr

orbit of H-atom is ​$v = \sqrt{\dfrac{kZe^{2} }{mr} }$