51) Find the LCM of the polynomials 5(x³-y³) and 35(x⁶-y⁶)
pls answer properly with clear steps
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2
Answer:
(x+y)³=x³+y3+3xy(x+y)
or 5³=35+3xy(5)
or 125−35=15xy
or xy=1590=6
Now, (x−y)2=(x+y)2−4xy
=52−4×6
=25−24=1
∴x−y=1=±1
Answered by
1
LCM of
5(x³-y³) and 35(x⁶-y⁶)
is
5(x³-y³) .
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