Question

51. If linear momentum (p), acceleration (a) and time
(T) are taken to be fundamental quantities, then
dimensional formula for mass is
(1) [p'a't'] (2) [p'a't")
(3) [p'al T]
(4) [p?a'79)​

Answer 1

Answer:

Answer is p a^-1 T^-1

Explanation:

Answer 2

The dimensional formula of mass is $pa^{-1}t^{-1}$

Explanation:

Momentum is given by :

$p=m\times v$ ......(1)

Velocity in terms of acceleration is given by :

$v=a\times t$

Put v in equation (1) as :

$p=m\times a\times t$

m is mass

a is acceleration

p is momentum

t is time

$m=\dfrac{p}{at}\\\\m=pa^{-1}t^{-1}$

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If linear momentum acceleration and time  are taken to be fundamental quantities, then  dimensional formula for mass is ?

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