51. If r is the radius of the atom in a crystal crystallizing in the simple cubic structure, then the nearest neighbour
distance is
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In a simple cubic lattice, two atoms touch each other along the edge of a cube.
Hence, the distance between the centres of the nuclei of two adjacent atoms is equal to the edge length of the cell which is a.
Hence, the nearest neighbour distance in a simple cubic lattice is r.
Explanation:
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