Question

51. In AABC, PQ || BC, area of quadrilateral PBCQ = 42sq.
cm. If AP: PB = 2:3, then find the area of AAPQ:
PQ TÖBG
APLIS
42
262.28
f
e
8432
С C
B
ale 89
56
sq. cm.
3
(B)
2
CAP.28 $9. cm.
su
198 sq. cm.
(D) 33.6 sq. cm.​

Answer 1

Answer:

In △ABC, PQ∥BC

∠BAC=∠PAQ ...... (Common angle)

∠ABC=∠AP ....... (Corresponding angles)

Thus, △AB∼△APQ

Ar(△APQ)

Ar(△ABC)

=

AP

2

AB

2

Ar(△APQ)

Ar(△APQ+Ar(□PBCQ)

=

4

25

x

x+42

=

4

25

⇒4x+168=25x

⇒21x=168

⇒x=8

Thus, Ar(△APQ)=8 sq.cm