Chemistry, asked by sudeep1028, 3 months ago


51 The Ionisation potential of Hydrogen is
2.17 x 10-11 erg/atom. The energy of the
electron in the second orbit of the hydrogen
atom is
2.17x10-11
1)
2.17 x 10-11
2
22
2.17 x 1017
3)
2.17 x 10"
22
22

Answers

Answered by jha515595
0

Answer:

sorry for that don't know sorry

Answered by manushreejnvd
0

Answer:

Energy of electron hydrogen atom is given by,

E

n

=−

n

2

2.178×10

−11

ergatom

−1

Therefore, for second orbit i.e n=2

E

2

=−

2

2

2.178×10

−11

ergatom

−1

I hope it is correct answer

please mark me as brainlest answer

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