51. The least number which when divided by 14,
35 and 42 leaves remainder in each case , is
(a) 210 (b) 216 (c) 280 (d) 252
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Answered by
3
Answer:
I think so (a) 210
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Answered by
3
Option 'a' is correct.
Step-by-step explanation:
Since we have given that
Let the least number be 'x'.
When it is divided by 14, 35 and 42
Then remainder leaves in each case
So, LCM of 14, 35 and 42 = 210
And 210 is divisible by 14 , 35 and 42.
Hence, Option 'a' is correct.
# learn more:
The largest number which divides 77, 147, and 252 leaving the same remainder in each case: a) 9 b)15 c)25 d) 35
https://brainly.in/question/1134640
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