51.
Volume of vessel is 1L. 1 mole of D is added from out
side. Equilibrium was re-established keeping
temperature constant. The amount of 'Creacts to
A
+ B =
C + D
At equilibrium 1M
1M
2M 1M
establish equilibrium is :
√2-1
(2)
(1)
2-2
2-12
√2+1
2
VE
(4) J2-1
(3) 12-1
Answers
Answer:
Concentration at I equilibrium 1515a (Volume = V litre)
Concentration when volume is doubled
2
15
2
15
2
a
(Volume = 2V litre)
Concentration at II equilibrium (
2
15
+x)(
2
15
+x)(
2
a
−x)
On increasing volume, the reaction proceeds in the direction where an increase in mole is noticed, i.e., backward reaction
∴
2
15
+x=10;∴x=
2
5
Since, for I equilibrium
K
c
=
[A][B]
[C]
=
15×15
a
...(i)
For II equilibrium
K
c
=
[A][B]
[C]
=
[(15/2)+(5/2)][(15/2)+(5/2)]
[(a/2)−(5/2)]
...(ii)
Since, K
c
are same and therefore by equations (i) and (ii)
a=45M
Also, by equation (i) K
c
=
15×15
45
=0.2mol
−1
litre