Question

51(y-4)(y^2+4y+4) by 17(y-4)(y+2) divide the number​

Answer 1

Answer:

3(y+2)=3y+6

Step-by-step explanation:

$\frac{51 ( y-4)(y^{2} +4y+4)}{17(y-4)(y+2)}$

cancel out (y-4) from numerator and denominator

=$\frac{51(y^{2} +4y+4)}{17(y+2)}$

we know $(y+2)^{2} = y^{2} + 4y+4$

hence cancel out one (y+2) from numerator and denominator

=$\frac{51 (y+2)}{17}$

=$3(y+2)=3y+6$

Q.E.D.

Answer 2

Answer:

quotient is 3y+6

Step-by-step explanation:

refer the images for clarity