Math, asked by ahirwarr61541, 1 year ago

51x+23y=116 and 23x +51y=106 then the value of x-y is

Answers

Answered by ShreyaSrivastava221
36

Answer:

5/14

Step-by-step explanation:

Let 51x+23y=116 be equation (1)

let 23x+51y=106 be equation (2)

equation (1)-equation(2)

51x+23y-(23x+51y)=116-106

51x+23y-23x-51y=10

51x-23x-51y+23y=10. ( rearranging the terms)

28x-28y=10

28(x-y)=10. ( 28 is common)

x-y=10/28

or after simplification (x-y)=5/14.

Answered by vidhya25
22

Answer:

Refer attachment

Step-by-step explanation:

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