Question

52[2-3{4+(7-8)-2+7}-4]

Answer 1

Hey,

Your answer,

>> 52[2-3{4+(7-8)-2+7}-4] or
>> 52[2-3{4-1-2+7}-4] or
>> 52[2-3(8)-4] or
>> 52[2-24-4] or
>> 52×(-26) or
>> -1352

Hope this helps!

Answer 2

Answer:

Required answer is (-1352).

Step-by-step explanation:

Given,

52[2-3{4+(7-8)-2+7}-4]

We can solve this problem by BODMAS rule.

By BODMAS rule,

Bracket -Of - Division - Multiplication - Addition - Subtraction

So, 52[2-3{4+(7-8)-2+7}-4]

= 52[2-3{4+(-1)-2+7}-4]

= 52[2-3{4-1-2+7}-4]

=52[2-3{11-3}-4]

=52[2-3{8}-4]

=52[2-24-4]

=52[-26]

=(-1352)

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x - + y)( {x}^{2} - xy + {y}^{2} )$

Know more about Algebra,

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