Question

[5² (8⅓+ 27⅓)³]⅕

so yea can anyone tell me how to do this :c​

Answer 1

Answer:

[25*(3√8+3√27) power 3] power 1/5

=[25*(2+3) power 3] power 1/5

=[25*125] power 1/5

=5√5*5*5*5*5

=5 answer

Answer 2

Answer:

5

Step-by-step explanation:

[$5^2$ ($8^\frac{1}{3}$ + $27^\frac{1}{3}$)^3]$^\frac{1}{5}$

$[5^2(2^3^\frac{1}{3} + 3^3\frac{^1}{3} )^3]^\frac{1}{5}$

$[5^2(5)^3]^\frac{1}{5}$

$[5^(^2^+^3^)]^\frac{1}{5}$

5