Physics, asked by Simrankemwal6689, 11 months ago

52 a ball of mass m moving with velocity v collides lon with the second ball of mass m at rest. If the coefficient of restitution is e and velocity of first hall after collision is v, and velocity of second ball after collision is v, then (1-e)u (1+ e)u (1) v 2 2 mass with energy (1) (3) 58 sele of (1+e)u (2) v (1-e)u (3) v2 2 (1) 21 (4) v = (1 + e)u, v2

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Answered by ʙʀᴀɪɴʟʏᴡɪᴛᴄh
2

Answer:

Let,the 1st ball will move with a velocity of v and the 2nd one with x after the collision. so, mu+m⋅0=m⋅v+m⋅x.........................

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