Question

52. A body is projected vertically upwards from ground with a velocity 'u' and it gains a maxi mum height 'H'm. At a point 'x'm height (x < H), the ratio of its potential to Kinetic energy is 1:2. Now if the body is projected upwards with a velocity '3u' from the ground, find the ratio of its potential to kinetic energy at a point whose height is '3x'm.​

Answer 1

Answer:

Initial Energy =KE  

i

​

=  

2

1

​

mu  

2

 

At Point x KE  

x

​

=  

2

1

​

mu  

2

−mgx

2

1

​

mu  

2

−mgx

mgx

​

=  

2

1

​

 

2mgx=  

2

1

​

mu  

2

−mgx

3mgx=  

2

1

​

mu  

2

 

3x=  

2g

u  

2

 

​

 

Now if u  

1

=3u

x  

1

=3x

KE  

3x

​

=  

2

1

​

mu  

1

 

2

−mgx  

1

⇒  

2

1

​

m9u  

2

−3mgx

PE  

3x

​

=mg

f  

1

=  

2

9

​

mu  

2

−3mgx

3mgx

​

⇒  

2g

9u  

2

 

​

−3x

3x

​

⇒  

27x−3x

3x

​

 

=  

24x

3x

​

 

=1:8

Explanation:

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Answer 2

Answer:

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