Question

52. ABCD is a trapezium with AB || CD. AB = 20 cm, CD = 10 cm and AM I CD. AM = 5 cm. Find the area
of the trapezium.
only 95% genius Einsteins can answer this.
let's see who can answer this. ​

Answer 1

Answer:

area of trapezium = 75cm^2

Step-by-step explanation:

area of trapezium = 1/2 ( a + b ) h = 1/2 (20+10) 5 =1/2 ×30×5 = 15×5 = 75 cm ^2

Answer 2

Answer : area=75sq cm

Step-by-step explanation:

Height=5cm as AM is perpendicular to CD

Area of trapezium = h*(sum of parallel side/2)

Then area = 5*(10/2+20/2)

=5*15

=75sq cm