52 g of He contains
(a) 4 x 6.022 x 10*23 atoms
(b) 13 atoms
(c) 13 x 6.022 x 10*23 atoms
(d) 4 atoms.
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(i) 52 moles of Ar
The number of atoms present in 52 mol of Ar can be calculated as follows.
1 moles of Ar = 6.022×1023 atoms of Ar
52 moles of Ar = 52 x 6.022 x 1023
∴ 52 moles of Ar = 3.13144 × 1025
(ii) 52 u of He
The atomic mass of He is 4 amu.
52 u of He will contain 52/4 = 13 atoms
(iii) 52 g of He
1 mole of He = 4 g = 6.022 × 10²³ atoms of He
52 grams of He will contain = 52/4 = 13 moles
Number of atoms in 13 moles of He = 13 × 6.022 × 1023atoms
Number of atoms in 13 moles of He = 78.29× 1023 atoms
52 grams of He = 7.829 × 1024 atoms
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