Question

52. Kc for 2 / H ₂ + 1 / 2
are
N = NH.
0.0266 and 0.0129 are respectively at
350°C and 400°C.Calculate heat of
formation of NH..​

Answer 1

Explanation:

∴△H=−12140cal

As we know,

2.303log[

K

P

1

​

​

K

P

2

​

​

​

]=

R

△H

​

[

T

1

​

T

2

​

T

2

​

−T

1

​

​

]

2.303log[

0.0266

0.0129

​

]=

2

△H

​

[

673×623

673−623

​

]

∴△H=12140cal=−12140cal