Question

52. The number of Cl- ions in 100 mL of 0.001
M HCl solution is
(a) 6.022 x 10^23 (b) 6.022 x 10^20
(c) 6.022 x 10^19 (d) 6.022 x 10^24​

Answer 1

Answer:

C

Explanation:

No. Of moles

No. Of moles of HCl = No. Of moles of Cl-

molarity×volume(in litres)

=> 0.001×0.1 = 0.0001

Therefore no. Of moles of Cl = 0.0001

=> Cl- ions =

6.022×10^23×0.0001

= 6.022×10^19

Hope it helps u