Question

52. The present age of the father is three times
than that of his son. After three years the
age of the father will be 7 years more than
twice the age of the son. The present age of
the son is
years​

Answer 1

$\Large{\underbrace{\underline{\bf{GIVEN\::}}}}$

• The present age of father is 3 times than that of his son.

$\Large{\underbrace{\underline{\bf{TO\:FIND\::}}}}$

• Present age of the son.

$\Large{\underbrace{\underline{\bf{SOLUTION\::}}}}$

Let,

• Present age of son is x.

☛ Present age of father = 3x

✳ After 3 years,

☛ Age of father = (3x + 3) years

☛ Age of son = (x + 3) years

According to the question,

✰ After three years the age of the father will be 7 years more than twice the age of the son.

➵ 3x + 3 = [2 × (x + 3)] + 7

➵ 3x + 3 = (2x + 6) + 7

➵ 3x + 3 = 2x + 13

➵ 3x - 2x = 13 - 3

➵ x = 10

∴ Present age of son is 10 years.

Answer 2

Step-by-step explanation:

$\begin{gathered}\Large{\underbrace{\underline{\bf{GIVEN\::}}}} \\ \end{gathered}$

The present age of father is 3 times than that of his son.

$\begin{gathered}\Large{\underbrace{\underline{\bf{TO\:FIND\::}}}} \\ \end{gathered}$

Present age of the son.

$\begin{gathered}\Large{\underbrace{\underline{\bf{SOLUTION\::}}}} \\ \end{gathered}$

Let,

Present age of son is x.

☛ Present age of father = 3x

✳ After 3 years,

☛ Age of father = (3x + 3) years

☛ Age of son = (x + 3) years

According to the question,

✰ After three years the age of the father will be 7 years more than twice the age of the son.

➵ 3x + 3 = [2 × (x + 3)] + 7

➵ 3x + 3 = (2x + 6) + 7

➵ 3x + 3 = 2x + 13

➵ 3x - 2x = 13 - 3

➵ x = 10

∴ Present age of son is 10 years..