Question

52. The sum of the digits of a number is
subtracted from the number. The
resulting number is always divisible
by
2
(2)
8
9
53.
The sum of first four multiples of 8
is
00
(2) 70
(3) 80
(4) 100​

Answer 1

Answer:

Let us work out with few numbers and get the answer

Let the number be 23.

Sum of digits is 2+3=5

Now, we subtract the sum of the digits from the number itself that is 23−5=18.

18 is divisible by both 2 and 9.

Similarly, Let the number be 15.

Sum of digits is 1+5=6

Now, we subtract the sum of the digits from the number itself that is 15−6=9.

9 is divisible by 9.

Hence, the sum of the digits of a number is subtracted from the number, the resulting number is always divisible by 9.

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