Question

52. The (W/Q) of a Carnot engine is 1/6. Now the
temperature of sink is reduced by 62°C, then this ratio becomes twice, therefore the initial temperature of the sink and source are respectively
(1) 33°C, 67°C
(2) 37°C, 99°C
(3) 67°C, 33°C
(4) 97K, 37K.

Answer 1

Explanation:

Hey Mate it seems pretty simple to solve

Efficiency of engine,n = 1/6

n=1-T'/T

Where T' is temperature of sink

And T is temperature of system

1/6=1-T'/T .....(1)

When temperature of sink is reduced by 335K

Than efficiency is 1/3

1/3=1-(T'-335)/T ....(2)

On solving equation (1) and (2)

You get

T'=37°C And T=99°C

Hope it helps you