Question

√5²-x- √5= 0 Find discriminant and write the nature of roots.​

Answer 1

Answer:

$d = {b}^{2} - 4ac \\ { (- 1)}^{2} - 4( \sqrt{5})( - \sqrt{5} ) \\ 1 + 20 \\ = 21$

Step-by-step explanation:

$d > 0 \\ so \: roots \: are \: real \: and \: distinct$

Answer 2

Answer:

The root in this question are 'Real' roots and the Discriminant is 1+(20×root5).

Step-by-step explanation:

Here, According to our question,

=(Root5)^2-x-root5=0

Here, Let, a=(Root5)^2, b=(-1), c=(-root5)

As formula to find out discriminant is,

=d=(b)^2-4(a)×(c)

=d=(-1)^2- 4×(root5)^2×(-root5)

=d=1-(-20×root 5)

=d=1+(20×root5)

Here, our discriminant is greater than zero,

So, in this question we have real roots

Thank you.