Question

5247 is not square give reson

Answer 1

Consider first 10 perfect squares.

1, 4, 9, 16, 25, 36, 49, 64, 81, 100.

Divide each square by 10 and write down each remainder thus formed.

1, 4, 9, 6, 5, 6, 9, 4, 1, 0,

On considering the next 10 perfect squares, we get the same sequence. On considering next 10 ones, this sequence will be got again. Thus the sequence is repeating over and over.

This sequence is the remainder got on dividing the perfect squares by 10. Thus these remainders are digits at ones place of each perfect square, because of the fact that a number leaves its ones digit as remainder on division by 10.

One feature of this sequence is that the numbers 2, 3, 7 and 8 are not in the sequence.

So according to this feature and the above concept underlined, we can conclude with the fact that,

Perfect squares don't leave remainder 2, 3, 7 or 8 on division by 10.

OR

Numbers ending in 2, 3, 7 or 8 are not perfect squares.

Given number is 5247, which ends in 7. So it is not a perfect square.