Question

525 gram of the higher oxidize oxide of metal on heating gave 5.225 gram of lower oxide the lower oxide on the reduction gives 4.9 25 gram of the metal Prove the law of multiple proportions from which book this is​

Answer 1

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As 5.575 g of lower oxide on reduction gives 5.175 g of the metal, the mass of the oxygen is 5.575 - 5.175 = 0.4 g

For 1 g of metal, mass of oxygen is 0.5 / 0.175 = 0.077 g

In case of higher oxides, mass of metal is 5.175 g Mass of oxygen is 5.975 —5.175= 0.8 g

For 1 g of metal, mass of oxygen is

0.8 /5.175 = 0.155 g

For a given mass of metal, the ratio of oxygen is 0.777:0.155 or 1:2. Hence, the law of multiple proportion is proved.