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if a + ib =0 then prove that a-ib=0 complex number
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it is only possible if b=0
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Step-by-step explanation:
A complex number, Z, has the form Z=x+i y Z=x+i y where xx and yy are real numbers and ii is the imaginary unit postulated such that ii² = −1−1. Quantity xx is the real part of Z and y is the imaginary part of Z. Please note that y is a Real quantity.
Therefore, A Real Number is thus a complex number with 0 Imaginary Part.
A complex number with 0 Real Part is a pure imaginary number.
The number which is both Real and Pure imaginary at the same time is 0.
It is, therefore, trivial to write 0 as 0 + i0 which hardly serves any meaningful purpose except for the sake of brevity. With this background, you are going wrong NOWHERE.
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