Question

52g of Al will react completely with how much mass of O2 to produce Al2O3?​

Answer 1

Answer:

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Explanation:

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Answer 2

Explanation:

the reaction is

Al +O2-------> Al2O3

we know

for 26g of Al oxygen required=32g

therefore for 52g of Al oxygen required=(32×52)÷26

= 32×2

=64

(answer)

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