52pqr(2pqr + p2q + pq2 + q2r + qr2 + p2r + pr2)÷ 104pq(q +r)(r + p)
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Answer:
Given, In ΔPQR
Refer image,
PR
2
−PQ
2
=QR
2
and QM⊥PR
To prove: MQ
2
=MP×MR
Proof: In ΔPQR
PR
2
−PQ
2
=QR
2
[Given]
PR
2
=PQ
2
+QR
2
∴ΔPQR=90
0
[By conv, of Pythagoras theorem]
Now in ΔQMP and ΔQMR
∠1=∠2=90
0
(∵QM⊥PR)
∠P=90
0
−∠R
∠3=90
0
−∠R
∠P=∠3
∴ΔQMP∼ΔRMQ (By AA similarity criterion)
QR
PQ
=
QM
PM
=
RM
QM
=QM
2
=PM×RM
Hence proved.
solution
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