Question

53. A box contains 20 cards
numbered from 1 to 20. A card is drawn at
random from the box. Find the probability
that the number on the drawn card is:
(1) divisible by 2 or 3
(ii
) a prime number
​

Answer 1

Answer:

1 ) 3/20 = 0.15

2) 7/20= 0.35

Answer 2

Answer:

Let E be event of drawing a card with number divisible by 2 or 3 from the cards with numbers 1 to 20

Numbers divisible by 2 or 3 from 1 to 20=2,3,4,6,8,9,10,12,14,15,16,18,20

No. of favorable outcomes=13

Total no. of possible outcomes =20

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

20

13

Therefore, the probability that a number on the card selected from numbers 1 to 20 divisible by 2 and 3 is

20

13

Solution(ii):

Let F be event of drawing a card with prime number from the cards with numbers 1 to 20

Prime numbers from 1 to 20=2,3,5,7,11,13,17,19

No. of favorable outcomes=8

Total no. of possible outcomes =20

We know that, Probability P(F) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

20

8

=

5

2

Therefore, the probability that a card with prime number is selected from numbers 1,2,3,...,20 =

5

2

Step-by-step explanation:

Mark me a brainlist