Question

53. A brick has 3 sides a, b, c (a > b> c). The brick
can be kept on ground on any face. The work
required to be done to move slowly from minimum
potential energy situation to maximum potential
energy situation of brick is:​

Answer 1

Answer:

mg=1=23 m=2=11.1in qmit

Answer 2

The work required to move a brick from its minimum potential energy situation to its maximum potential energy situation depends on the gravitational force acting on the brick and the distance over which the brick is moved.

• In this case, the minimum potential energy situation of the brick is when it is resting on its smallest face (side c), and the maximum potential energy situation is when it is resting on its largest face (side a).

• The work done to move the brick from its minimum potential energy situation to its maximum potential energy situation is equal to the change in gravitational potential energy of the brick. The change in gravitational potential energy of the brick is equal to the weight of the brick multiplied by the distance it is moved vertically.

• So, the work done to move the brick from its minimum potential energy situation to its maximum potential energy situation is (Weight of brick) * (Distance moved vertically)

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