Question

53. One die and a coin are tossed simultaneously. The probability of getting 5 on the top of the die and tail on the coin is
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Answer 1

Answer:

As a die have 6 face, and assuming that it is a normal die, the numbers will be from 1 to 6. There are two composite numbers in this set which are 4 and 6. so here the probability will be 2/6 i.e., 1/3

Coin

A coin has two sides head and tail. So the probability of getting a tail will be 1/2

As you mentioned composite number or tail, it will be union

Considering Die as D and Coin as C

P(D∪C)= P(D)+P(C)-P(D∩C)

=>P(D∪C)= 1/3+1/2–(1/2)*(1/3)

=>P(D∪C)=2/3

Here we have subtracted P(D∩C) because that event occurs with both D and C, as we have to consider it only once but we did add them twice in both P(D) and P(C) we have to subtract for once.

Method 2:

Consider all possible events and count them

1 T

2 T

3 T

4 T

5 T

6 T

1 H

2 H

3 H

4 H

5 H

6 H

Here the likely events are 8 and total events are 12, which means the probability is 8/12 i.e., 2/3

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Answer

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42 answers

843 people helped

probability of tail on coin is 1/2 and probability of getting 5 on die is 1/6

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Answer:

Refer to the attachment...:D