Question

53. The area of square, whose perimeter is 48 m is.
(1) 48 m2(2) 144m2(3) 1152 m2 (4) 2304 m2

54. The average of 20 values is 18. If 3 is
subtracted from each of the values, then the new average will be.
(1) 21 (2) 15 (3) 16 (4) 17

55. Two numbers are in the ratio 2:3. If 9 is added to each, they will be in the ratio 3:4, the numbers are.
(1) 12, 28 (2) 18,27 (3) 8,12 (4) 10,15

56. What is the volume of a box whose each edge measures 3 m in length?
(1) 54 cu m (2) 27 cu m (3) 18 cu m (4) 9 cu m​

Answer 1

so here's your answer ......hope it helps u

Answer 2

Answer:

53. Option 2 is correct.

54. Option 2 is correct.

55. Option 2 is correct.

56. Option 2 is correct.

Step-by-step explanation:

Answer 1:-

Given that-

Perimeter of square = 48 m

Area of square =?

We know that-

Perimeter of square = 4a

Where a is a side of square

4a = 48

$a = \dfrac{48}{4}$

a = 12

$Area \ of \ square = a^{2}$

                              $= (12)^{2}$

$Area \ of \ square = 144 \ m^{2}$

Hence, option 2 is correct.

Answer 2:-

Given that-

The average of 20 values = 18

Now, 3 is subtract from each of the value.

Then new average =?

We know that-

If k subtracted from each value then the new average = old average - k

The new average = 18 - 3

The new average = 15

Hence, option 2 is correct.

Answer 3:-

Given that-

Ratio of two numbers = 2 : 3

Let A and B are two numbers. Then

A : B = 2 : 3

Let A = 2x

B = 3x

Now, 9 added to each numbers. Then

A = 2x + 9

B = 3x + 9

Ratio = 3 : 4

A : B = 3 : 4

$\dfrac{2x + 9}{3x + 9} = \dfrac{3}{4}$

4(2x + 9) = 3(3x + 9)

8x + 36 = 9x + 27

8x - 9x = 27 - 36

-x = -9

x = 9

So, A = 2x

         = 2×9

A = 18

B = 3x

  = 3×9

B = 27

Hence, the numbers are 18 and 27.

So, option 2 is correct.

Answer 4:-

Given that-

The edge of box = 3 m

Volume =?

We know that-

If a is any edge of any box then the volume of box-

$V = a^{3}$

$V = (3)^{3}$

$V = 27 \ m^{3}$

Hence, option 2 is correct.