Question

53. The product of two consecutive numbers is 600. Then,
the sum of their squares is
(a) 1203 (b) 1206 (c) 1201 (d) 1204​

Answer 1

Answer:

1201

Step-by-step explanation:

let one no be X

other be Y

A.T.Q

X(X+1)=600

x^2+x-600=0

by quadratic formula

D=b^2-4ac

1+2400

=2401

X=-b+-✓D/2a

-1+-√2401/2

-1+49/2

=24

X=24

X+1=25

24^2+25^2

576+625

1201