Math, asked by anmolbhardwaj575, 6 months ago

54.64 m
(13-1)
4.A man 1.8 m tall stands at a distance of 3.6 m from a lamp post and casts a shadow of
54 m on the ground. Find the height of the lamp post.
Hint. Let AB be the lamp post and CD be the man.
40
(√3+1)
X Х
( 13 +1)
2
2
XQ
3
13
x
13
3
(31.55 x 2
x 2% 13 ) = (63.1 x 1.732) m = 109.28 m)
XQ
= cosec 60° =
PQ
3
94.44 %
71
1.8 m
E
1
5.4 m
с a
3.6 m
Let CE be the shadow of CD. Then
CD 1.8 1
tan 0 =
СЕ 5.4 3
BF BF
Also, =tan O
1
= BF
3
DF 3.6
= 1.2 m. Find AB.]
15. In the adjoining figure, a man stands on the ground at a point A, which
is on the same horizontal plane as B, the foot of the vertical pole BC.
The height of the pole is 10 m. The man's eye is 2 m above the ground,
He observes the angle of elevation of C, the top of the pole as xº, where
Calculate the distance AB in metres.
5
2
tan x
E
> 2 mo
00​

Answers

Answered by gulabiyadav3
0

Answer:

73637717748488488q77366266184

Answered by kulkarninishant346
1

Answer:

itz too long dude ok see in google haldi soh padhai maat kar aub kyuki tera murder karne koh aahuga ok aur match dekh ja

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