Question

54. A body projected vertically up crosses points A and B
separated by 28 m with velocities one-third and one-
fourth of the initial velocity, respectively. What is the
maximum height reached by it above the ground?​

Answer 1

Answer:

576 m.

Explanation:

u² - v² = 2gh

now

for point A :

2gh1 = u² - u²/9 = 8u²/9 = 128u²/144

for point B :

2gh2 = u² - u²/16 = 15u²/16 = 135u²/144

2g(h2-h1) = 56g = 7u²/144

u² = 144(8g)

maximum height reached = u²/2g = 144(8g)/2g = 144(4) =24² = 576 m.