Question

54 and 84 marbels are to be packed into small container such that each container has equal number of marbels .Find the greatest number of marbels that can be packed in each small packet

Answer 1

Answer:

138

Step-by-step explanation:

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Answer 2

Answer:

6

Step-by-step explanation:

The answer is 6 because in the question it is mentioned we need to find the greatest number which refers to the method HCF therefore the working would be as followed,

Find the prime factorization of 54

54 = 2 × 3 × 3 × 3

Find the prime factorization of 84

84 = 2 × 2 × 3 × 7

Now we shall find the common factors which are as follow,

2 x 3 = 6

Therefore the greatest number in each small packet is 6.

Hope this helped...