54 g of Aluminium and 320 g of oxygen gas react to form
Aluminium oxide formed.Calculate the mass of Al2O3 formed.
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Explanation:
4Al + 3O2 = 2Al2O3
Molar mass of Al = 27 g
Molar mass of Oxygen molecule = 32 g
Hence the Al and oxygen reacted in 1:1 molar ratio
Al is the limiting reactant as there is not sufficient of it to react with excess oxygen, as from the equation 1 mole of Al forms half mole of aluminium oxide, the molar mass of aluminium oxide is 27*2 + 16*3 = 102
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