Question

54 GM's of aluminium reacts with 160gms of oxygen find out the weight of product​

Answer 1

Explanation:

The balanced chemical equation is as follows:

4Al+3O

2

→2Al

2

O

3

.

Here, 4 moles (4×27g) of aluminum reacts with 3 moles (3×32g) of oxygen.

Thus, the weight of oxygen required to completely react with 27 g of aluminum is (3×32g)×

(4×27g)

(27g)

=24 gm