Math, asked by theayushbaba, 4 months ago


54. The maximum value of Z = 3x + 2y
subject to constraints x + 2 y 310
3x + y =15
* 20 y 20 is
(A) 0
(B) 15
(C) 10
a - b b-c c - а
(D) 18​

Answers

Answered by barbiedoll275
0

Answer:

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