Question

54) The time of ascent of a body thrown vertically upward with initial velocity u is
(a) t= u/2g (b) t= u/g (c) t= u2/g (d) t= u/g2​

Answer 1

Answer:

option b

Explanation:

v=u-gt ( when body moves against gravity)

v=0 so, on substituting,

0=u-gt

u=gt

t=u/g

hope u are satisfied with the answer