Question

540 grams of ice at zero degree celsius is mixed with 540 gram of water at 80 degree celsius the final temperature of the mixture is if the latent heat of fusion of ice is 80 cal /gram and specific heat of water is 1 cal/ g°Celsius

Answer 1

Here is your answer:

The ice at 0℃ will absorb heat from water at 80℃ to become water and the temperature will rise.

Let the final temperature becomes T℃

heat absorbed by ice = heat given by water

540 × 80 + 540 × (T - 0) × 1 = 540 × (80-T) × 1

43200 + 540 T = 43200 - 540T

540T + 540T = 43200 - 43200

1080T = 0

T = 0/1080 = 0℃

So the temperature remains at 0℃ but all ice is converted into water. Here all the energy absorbed from the water at 80℃ is used to convert ice into water.

Hope you understood. if not, ask in comment box.

-Riki

Answer 2

It must be 0 degee Celsius bcoz according to calorimeter principle heat gain is equal to heat loss