Math, asked by niranjanlambture1, 1 year ago

540 man days of work can be completed by a certain number of men in some days. If the numbers of people (men) are increased by
27. then the number of day required to complete the same work is decreased by 15. The number of days are required to complete the
three times work (than the previous/actual work) 67 27 men?
Option
50
60
54
45​

Answers

Answered by amitnrw
2

Answer:

60 Days

Step-by-step explanation:

540 man days of work  = m * d

540 man days of work  = (m+ 27) * (d-15)

=> (m+ 27) * (d-15)  = md

=> md + 27d - 15m - 405 = md

=> 27d - 15m = 405

=> 9d - 5m = 135

=> 9d - 5(540/d) = 135

=> 9d²  - 5(540) = 135d

=> d² - 300 = 15d

=> d² - 15d - 300 = 0

=> d = 26.37 days

for 3 times works number of days required = 3 * 26.37  ≈ 79 days

work = 540 man days

3 times work = 3 * 540 = 1620 Man days

days required by 27 men = 1620/27  = 60 Days

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