5400,Find the smallest number by which the given number must be divided to obtain a perfect cube.
Answers
Answered by
33
Hi ,
Write given number as product of
prime numbers.
5 | 5400
________
5 | 1080
________
3 | 216
________
3| 72
________
3| 24
________
2| 8
________
2 | 4
________
2 | 2
_________
2 | 1
Therefore ,
5400 = 5 × 5 × 3 ×3×3×2×2×2
= ( 2 × 2 × 2 ) × ( 3 × 3 × 3 ) × 5 × 5
Here ,
5 is not in a group of 3 .
We have to divide given number with
( 5 × 5 = 25 ) to make it perfect cube .
Now it becomes.
5400/25= 216
216 = 6³ ( perfect cube )
I hope this helps you.
: )
Write given number as product of
prime numbers.
5 | 5400
________
5 | 1080
________
3 | 216
________
3| 72
________
3| 24
________
2| 8
________
2 | 4
________
2 | 2
_________
2 | 1
Therefore ,
5400 = 5 × 5 × 3 ×3×3×2×2×2
= ( 2 × 2 × 2 ) × ( 3 × 3 × 3 ) × 5 × 5
Here ,
5 is not in a group of 3 .
We have to divide given number with
( 5 × 5 = 25 ) to make it perfect cube .
Now it becomes.
5400/25= 216
216 = 6³ ( perfect cube )
I hope this helps you.
: )
Answered by
0
the answer is 5400 must be divided answer becomes 25
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